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I have been trying to use trim() for json key value pair , but it seems not to work, can anyone please help ?
var user = { first_name: "CSS",
last_name: " H ",
age: 41,
website: "java2s"
};
for (var key in user) {
console.log((key+"-->"+user[key].trim());
}
I have been trying to use trim() for json key value pair , but it seems not to work, can anyone please help ?
var user = { first_name: "CSS",
last_name: " H ",
age: 41,
website: "java2s."
};
for (var key in user) {
console.log((key+"-->"+user[key].trim());
}
3 Answers
Reset to default 3Assign the trimmed value to the specific user[key]:
var user = { first_name: "CSS", last_name: " H ", age: 41, website: "java2s." };
for (var key in user) {
user[key] = user[key].toString().trim()
console.log(key+"-->"+user[key]);
}Also, if you cannot use .trim() because of older browsers, use a polyfill for that.
Remended:
function trim(string) {
return string.replace(/^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g, '');
};
Evil edition:
if (!String.prototype.trim) {
String.prototype.trim = function () {
return this.replace(/^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g, '');
};
}
All browsers since IE9+ have trim()
For those browsers who does not support trim(), you can use this polyfill from MDN:
if (!String.prototype.trim) {
(function() {
// Make sure we trim BOM and NBSP
var rtrim = /^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g;
String.prototype.trim = function() {
return this.replace(rtrim, '');
};
})();
}
That's because you can't access a JSON value like:
var value = json[key]; // Wrong
You must do it like this:
var value = json.key; // Correct
I have been trying to use trim() for json key value pair , but it seems not to work, can anyone please help ?
var user = { first_name: "CSS",
last_name: " H ",
age: 41,
website: "java2s"
};
for (var key in user) {
console.log((key+"-->"+user[key].trim());
}
I have been trying to use trim() for json key value pair , but it seems not to work, can anyone please help ?
var user = { first_name: "CSS",
last_name: " H ",
age: 41,
website: "java2s."
};
for (var key in user) {
console.log((key+"-->"+user[key].trim());
}
3 Answers
Reset to default 3Assign the trimmed value to the specific user[key]:
var user = { first_name: "CSS", last_name: " H ", age: 41, website: "java2s." };
for (var key in user) {
user[key] = user[key].toString().trim()
console.log(key+"-->"+user[key]);
}Also, if you cannot use .trim() because of older browsers, use a polyfill for that.
Remended:
function trim(string) {
return string.replace(/^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g, '');
};
Evil edition:
if (!String.prototype.trim) {
String.prototype.trim = function () {
return this.replace(/^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g, '');
};
}
All browsers since IE9+ have trim()
For those browsers who does not support trim(), you can use this polyfill from MDN:
if (!String.prototype.trim) {
(function() {
// Make sure we trim BOM and NBSP
var rtrim = /^[\s\uFEFF\xA0]+|[\s\uFEFF\xA0]+$/g;
String.prototype.trim = function() {
return this.replace(rtrim, '');
};
})();
}
That's because you can't access a JSON value like:
var value = json[key]; // Wrong
You must do it like this:
var value = json.key; // Correct
本文标签： javascriptremove whitespace inside json object key value pairStack Overflow
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