options - Using get_option() for check box field

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I am trying to have a check field saved to database. it works . but in get_option i am passing the default value. but even if disable the checkbox(value 0) the field shows as ticked ..this is my code

<?php     
 $fields_default = array(
                0 => array(
                    'id'             => 0,
                    'checkbox_check' => '1',
                ),
                1 => array(
                    'id'             => 1,
                    'checkbox_check' => '0',
                ));

            $orderdescider = get_option('fields_new', $fields_default);

            foreach ($orderdescider as $checkfieldstatus) {
               if (isset($checkfieldstatus['id'])) {$id = $checkfieldstatus['id'];}
                if (isset($checkfieldstatus['checkbox_check'])) {$checkbox_check = $checkfieldstatus['checkbox_check'];} else { $checkbox_check = '0';}
                ?>

                <li class="sortable-item flexit">
                <div class="form-check">
                <input type="checkbox" class="form-check-input" id="exampleCheck1" name="orderdescider[<?php echo $id; ?>][checkbox_check]" value="1"<?php checked(isset($orderdescider[$id]['checkbox_check']));?> />
                 </div></li>
                <?php

            }

please help thanks

I am trying to have a check field saved to database. it works . but in get_option i am passing the default value. but even if disable the checkbox(value 0) the field shows as ticked ..this is my code

<?php     
 $fields_default = array(
                0 => array(
                    'id'             => 0,
                    'checkbox_check' => '1',
                ),
                1 => array(
                    'id'             => 1,
                    'checkbox_check' => '0',
                ));

            $orderdescider = get_option('fields_new', $fields_default);

            foreach ($orderdescider as $checkfieldstatus) {
               if (isset($checkfieldstatus['id'])) {$id = $checkfieldstatus['id'];}
                if (isset($checkfieldstatus['checkbox_check'])) {$checkbox_check = $checkfieldstatus['checkbox_check'];} else { $checkbox_check = '0';}
                ?>

                <li class="sortable-item flexit">
                <div class="form-check">
                <input type="checkbox" class="form-check-input" id="exampleCheck1" name="orderdescider[<?php echo $id; ?>][checkbox_check]" value="1"<?php checked(isset($orderdescider[$id]['checkbox_check']));?> />
                 </div></li>
                <?php

            }

please help thanks

• options

Share Improve this question edited Nov 7, 2018 at 16:51 asked Nov 7, 2018 at 16:13 user145078user145078 20

• 1 I'm unable to replicate your code, I get the following error code: Parse error: syntax error, unexpected '$orderdescider' (T_VARIABLE) – Remzi Cavdar Commented Nov 7, 2018 at 16:23
• Could you paste all your code, so that I can take a look at it? – Remzi Cavdar Commented Nov 7, 2018 at 16:23
• @RemziCavdar actually the array was not closed, please have a check now – user145078 Commented Nov 7, 2018 at 16:25
• 1 I also get Notice: Undefined variable: value_new – Remzi Cavdar Commented Nov 7, 2018 at 16:49
• 1 I don't know the answer, but I get help you out with your coding style, so that it is more readble, see: pastebin/Eimh4RZ5 – Remzi Cavdar Commented Nov 7, 2018 at 17:00

 |  Show 15 more comments

1 Answer 1

Sorted by: Reset to default 0

This may not exactly answer the question, but let's see the issues with your code:

1. If you want to save the data in the same format as the default value ($fields_default), then:

   1. Start your foreach like so: foreach ( $orderdescider as $i => $item ).

   2. Then inside that foreach, $id and $checkbox should always be set and defined like so:

      $id = isset( $item['id'] ) ? $item['id'] : '';
      $checkbox_check = isset( $item['checkbox_check'] ) ? $item['checkbox_check'] : '';
      

   3. And use the appropriate value in the field's name:

      <input type="hidden" name="orderdescider[<?php echo $i; ?>][id]"
        value="<?php echo $id; ?>">
      
      <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
        value="1" ...>
      

2. For the checkbox fields, you can use this format when writing the markup:

   <input type="checkbox" value="{value}"<?php // wrapped for clarity
     checked( '{value}', '{current/saved value}' ) ?> ...>
   

   so in your case, it would look like this:

   <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
     value="1"<?php checked( '1', $checkbox_check ) ?> ...>
   

   where 1 is the {value}, and $checkbox_check is the {current/saved value}.

   (See the reference for more details about using the checked() function.)

Hope that helps, and here's the full foreach code I used for testing: (I omitted the field's id, but make sure to use unique values)

foreach ($orderdescider as $i => $item) {
    $id = isset( $item['id'] ) ? $item['id'] : '';
    $checkbox_check = isset( $item['checkbox_check'] ) ? $item['checkbox_check'] : '';
    ?>
    <li class="sortable-item flexit">
        <div class="form-check">
            <input type="hidden" name="orderdescider[<?php echo $i; ?>][id]"
              value="<?php echo $id; ?>">
            <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
              value="1"<?php checked( '1', $checkbox_check ) ?> class="form-check-input">
        </div>
    </li>
    <?php
}

I am trying to have a check field saved to database. it works . but in get_option i am passing the default value. but even if disable the checkbox(value 0) the field shows as ticked ..this is my code

<?php     
 $fields_default = array(
                0 => array(
                    'id'             => 0,
                    'checkbox_check' => '1',
                ),
                1 => array(
                    'id'             => 1,
                    'checkbox_check' => '0',
                ));

            $orderdescider = get_option('fields_new', $fields_default);

            foreach ($orderdescider as $checkfieldstatus) {
               if (isset($checkfieldstatus['id'])) {$id = $checkfieldstatus['id'];}
                if (isset($checkfieldstatus['checkbox_check'])) {$checkbox_check = $checkfieldstatus['checkbox_check'];} else { $checkbox_check = '0';}
                ?>

                <li class="sortable-item flexit">
                <div class="form-check">
                <input type="checkbox" class="form-check-input" id="exampleCheck1" name="orderdescider[<?php echo $id; ?>][checkbox_check]" value="1"<?php checked(isset($orderdescider[$id]['checkbox_check']));?> />
                 </div></li>
                <?php

            }

please help thanks

I am trying to have a check field saved to database. it works . but in get_option i am passing the default value. but even if disable the checkbox(value 0) the field shows as ticked ..this is my code

<?php     
 $fields_default = array(
                0 => array(
                    'id'             => 0,
                    'checkbox_check' => '1',
                ),
                1 => array(
                    'id'             => 1,
                    'checkbox_check' => '0',
                ));

            $orderdescider = get_option('fields_new', $fields_default);

            foreach ($orderdescider as $checkfieldstatus) {
               if (isset($checkfieldstatus['id'])) {$id = $checkfieldstatus['id'];}
                if (isset($checkfieldstatus['checkbox_check'])) {$checkbox_check = $checkfieldstatus['checkbox_check'];} else { $checkbox_check = '0';}
                ?>

                <li class="sortable-item flexit">
                <div class="form-check">
                <input type="checkbox" class="form-check-input" id="exampleCheck1" name="orderdescider[<?php echo $id; ?>][checkbox_check]" value="1"<?php checked(isset($orderdescider[$id]['checkbox_check']));?> />
                 </div></li>
                <?php

            }

please help thanks

• options

Share Improve this question edited Nov 7, 2018 at 16:51 asked Nov 7, 2018 at 16:13 user145078user145078 20

• 1 I'm unable to replicate your code, I get the following error code: Parse error: syntax error, unexpected '$orderdescider' (T_VARIABLE) – Remzi Cavdar Commented Nov 7, 2018 at 16:23
• Could you paste all your code, so that I can take a look at it? – Remzi Cavdar Commented Nov 7, 2018 at 16:23
• @RemziCavdar actually the array was not closed, please have a check now – user145078 Commented Nov 7, 2018 at 16:25
• 1 I also get Notice: Undefined variable: value_new – Remzi Cavdar Commented Nov 7, 2018 at 16:49
• 1 I don't know the answer, but I get help you out with your coding style, so that it is more readble, see: pastebin/Eimh4RZ5 – Remzi Cavdar Commented Nov 7, 2018 at 17:00

 |  Show 15 more comments

1 Answer 1

Sorted by: Reset to default 0

This may not exactly answer the question, but let's see the issues with your code:

1. If you want to save the data in the same format as the default value ($fields_default), then:

   1. Start your foreach like so: foreach ( $orderdescider as $i => $item ).

   2. Then inside that foreach, $id and $checkbox should always be set and defined like so:

      $id = isset( $item['id'] ) ? $item['id'] : '';
      $checkbox_check = isset( $item['checkbox_check'] ) ? $item['checkbox_check'] : '';
      

   3. And use the appropriate value in the field's name:

      <input type="hidden" name="orderdescider[<?php echo $i; ?>][id]"
        value="<?php echo $id; ?>">
      
      <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
        value="1" ...>
      

2. For the checkbox fields, you can use this format when writing the markup:

   <input type="checkbox" value="{value}"<?php // wrapped for clarity
     checked( '{value}', '{current/saved value}' ) ?> ...>
   

   so in your case, it would look like this:

   <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
     value="1"<?php checked( '1', $checkbox_check ) ?> ...>
   

   where 1 is the {value}, and $checkbox_check is the {current/saved value}.

   (See the reference for more details about using the checked() function.)

Hope that helps, and here's the full foreach code I used for testing: (I omitted the field's id, but make sure to use unique values)

foreach ($orderdescider as $i => $item) {
    $id = isset( $item['id'] ) ? $item['id'] : '';
    $checkbox_check = isset( $item['checkbox_check'] ) ? $item['checkbox_check'] : '';
    ?>
    <li class="sortable-item flexit">
        <div class="form-check">
            <input type="hidden" name="orderdescider[<?php echo $i; ?>][id]"
              value="<?php echo $id; ?>">
            <input type="checkbox" name="orderdescider[<?php echo $i; ?>][checkbox_check]"
              value="1"<?php checked( '1', $checkbox_check ) ?> class="form-check-input">
        </div>
    </li>
    <?php
}

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