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I have an 8-bit hex decimal which is in aarrggbb format. I need methods to convert this to rrggbbaa format and vise versa. For eg

ARGB format

#FFFF2323

What i need is RGBA format

#FF2323FF

I have an 8-bit hex decimal which is in aarrggbb format. I need methods to convert this to rrggbbaa format and vise versa. For eg

ARGB format

#FFFF2323

What i need is RGBA format

#FF2323FF

• javascript
• colors
• rgba
• argb

Share Improve this question Follow asked Jun 26, 2018 at 7:39 Sachila RanawakaSachila Ranawaka 41.5k88 gold badges6161 silver badges8787 bronze badges 3

• 3 so, you have a string #FFFF2323? you want '#FFFF2323'.replace(/#(..)(......)/, '#$2$1') – Jaromanda X Commented Jun 26, 2018 at 7:41
• @JaromandaX Very elegant solution. Please make it an answer to the question :-) – Emil S. Jørgensen Commented Jun 26, 2018 at 7:45
• where did that non regex answer go! It was fine – Jaromanda X Commented Jun 26, 2018 at 7:51

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 5

If you're dealing with a string #FF123456

let x = '#FF123456';
console.log(x.replace(/#(..)(......)/, '#$2$1'));

If, however, x is a number, 0xFF123456 -

let x = 0xFF123456
console.log(`#${(x & 0x0FFFFFF).toString(16).padStart(6, '0')}${(x >>> 24).toString(16).padStart(2, '0')}`);

All you have to do is move a[1] and a[2] to the end

var a = "#AABBCCDD";

var b = "#"+a.slice(3,9)+a[1]+a[2];

I have an 8-bit hex decimal which is in aarrggbb format. I need methods to convert this to rrggbbaa format and vise versa. For eg

ARGB format

#FFFF2323

What i need is RGBA format

#FF2323FF

I have an 8-bit hex decimal which is in aarrggbb format. I need methods to convert this to rrggbbaa format and vise versa. For eg

ARGB format

#FFFF2323

What i need is RGBA format

#FF2323FF

• javascript
• colors
• rgba
• argb

Share Improve this question Follow asked Jun 26, 2018 at 7:39 Sachila RanawakaSachila Ranawaka 41.5k88 gold badges6161 silver badges8787 bronze badges 3

• 3 so, you have a string #FFFF2323? you want '#FFFF2323'.replace(/#(..)(......)/, '#$2$1') – Jaromanda X Commented Jun 26, 2018 at 7:41
• @JaromandaX Very elegant solution. Please make it an answer to the question :-) – Emil S. Jørgensen Commented Jun 26, 2018 at 7:45
• where did that non regex answer go! It was fine – Jaromanda X Commented Jun 26, 2018 at 7:51

Add a ment  | 

2 Answers 2

Sorted by: Reset to default 5

If you're dealing with a string #FF123456

let x = '#FF123456';
console.log(x.replace(/#(..)(......)/, '#$2$1'));

If, however, x is a number, 0xFF123456 -

let x = 0xFF123456
console.log(`#${(x & 0x0FFFFFF).toString(16).padStart(6, '0')}${(x >>> 24).toString(16).padStart(2, '0')}`);

All you have to do is move a[1] and a[2] to the end

var a = "#AABBCCDD";

var b = "#"+a.slice(3,9)+a[1]+a[2];

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