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let's say I have a function:

 function test1() {

       }

I want to return "test1" from within itself. I found out that you can do arguments.callee which is going to return the whole function and then do some ugly regex. Any better way?

what about namespaced functions?

is it possible to get their name as well: e.g.:

var test2 = 
{
 foo: function() {
    }
};

I want to return foo for this example from within itself.

update: for arguments.callee.name Chrome returns blank, IE9 returns undefined. and it does not work with scoped functions.

let's say I have a function:

 function test1() {

       }

I want to return "test1" from within itself. I found out that you can do arguments.callee which is going to return the whole function and then do some ugly regex. Any better way?

what about namespaced functions?

is it possible to get their name as well: e.g.:

var test2 = 
{
 foo: function() {
    }
};

I want to return foo for this example from within itself.

update: for arguments.callee.name Chrome returns blank, IE9 returns undefined. and it does not work with scoped functions.

• javascript
• jquery

Share Improve this question Follow edited Feb 23, 2012 at 22:59 user194076 asked Feb 23, 2012 at 22:49 user194076user194076 9,0372424 gold badges101101 silver badges158158 bronze badges 3

• 1 possible dup stackoverflow./questions/2648293/… – ajax333221 Commented Feb 23, 2012 at 22:52
• possible duplicate of Does javascript function know its name and Get function name in javascript. – Felix Kling Commented Feb 23, 2012 at 22:53
• Possible duplicate of How to get the function name from within that function? – Dan Dascalescu Commented Jun 12, 2019 at 19:53

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 7

var test2 = {
   foo: function() {
   }
};

You aren't giving the function a name. You are assigning the foo property of test2 to an anonymous function.

arguments.callee.name only works when functions are declared using the function foo(){} syntax.

This should work:

var test2 = {
   foo: function foo() {
      console.log(arguments.callee.name); // "foo"
   }
};

let's say I have a function:

 function test1() {

       }

I want to return "test1" from within itself. I found out that you can do arguments.callee which is going to return the whole function and then do some ugly regex. Any better way?

what about namespaced functions?

is it possible to get their name as well: e.g.:

var test2 = 
{
 foo: function() {
    }
};

I want to return foo for this example from within itself.

update: for arguments.callee.name Chrome returns blank, IE9 returns undefined. and it does not work with scoped functions.

let's say I have a function:

 function test1() {

       }

I want to return "test1" from within itself. I found out that you can do arguments.callee which is going to return the whole function and then do some ugly regex. Any better way?

what about namespaced functions?

is it possible to get their name as well: e.g.:

var test2 = 
{
 foo: function() {
    }
};

I want to return foo for this example from within itself.

update: for arguments.callee.name Chrome returns blank, IE9 returns undefined. and it does not work with scoped functions.

• javascript
• jquery

Share Improve this question Follow edited Feb 23, 2012 at 22:59 user194076 asked Feb 23, 2012 at 22:49 user194076user194076 9,0372424 gold badges101101 silver badges158158 bronze badges 3

• 1 possible dup stackoverflow./questions/2648293/… – ajax333221 Commented Feb 23, 2012 at 22:52
• possible duplicate of Does javascript function know its name and Get function name in javascript. – Felix Kling Commented Feb 23, 2012 at 22:53
• Possible duplicate of How to get the function name from within that function? – Dan Dascalescu Commented Jun 12, 2019 at 19:53

Add a ment  | 

1 Answer 1

Sorted by: Reset to default 7

var test2 = {
   foo: function() {
   }
};

You aren't giving the function a name. You are assigning the foo property of test2 to an anonymous function.

arguments.callee.name only works when functions are declared using the function foo(){} syntax.

This should work:

var test2 = {
   foo: function foo() {
      console.log(arguments.callee.name); // "foo"
   }
};

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