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Think of an object array, each of them having certain array properties like versions, targets. I want to ungroup objects for each version and target. 

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]

Desired output for myArray above would be:

[
  { 'name': 'a', version: 1,         target: 'server1'},
  { 'name': 'a', version: 1,         target: 'server2'},
  { 'name': 'a', version: 2,         target: 'server1'},
  { 'name': 'a', version: 2,         target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server1'},
  { 'name': 'b', version: undefined, target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server3'},
  { 'name': 'c', version: 1,         target: undefined},
]

I pondered using nested for/forEach loops, but am almost pretty sure there must be a more precise and reasonable way of achieving it built-in es6 functions or so. And that's what I'm asking for.

Think of an object array, each of them having certain array properties like versions, targets. I want to ungroup objects for each version and target. 

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]

Desired output for myArray above would be:

[
  { 'name': 'a', version: 1,         target: 'server1'},
  { 'name': 'a', version: 1,         target: 'server2'},
  { 'name': 'a', version: 2,         target: 'server1'},
  { 'name': 'a', version: 2,         target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server1'},
  { 'name': 'b', version: undefined, target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server3'},
  { 'name': 'c', version: 1,         target: undefined},
]

I pondered using nested for/forEach loops, but am almost pretty sure there must be a more precise and reasonable way of achieving it built-in es6 functions or so. And that's what I'm asking for.

  • javascript
  • arrays
  • ecmascript-6
Share Improve this question asked Dec 18, 2019 at 7:36 vahdetvahdet 6,75910 gold badges62 silver badges116 bronze badges 1
  • 1 There isn't a native method that I know of off-the-bat: I guess that's because what you're seeing essentially is creating all possible binations of versions + targets. That would call for a basic for loop, and it will grow in plexity the more dimensions you have, since the more nested the loops will have to be. – Terry Commented Dec 18, 2019 at 7:39
Add a ment  | 

4 Answers 4

Reset to default 6

You could use .flatMap:

  const notEmpty = arr => arr.length ? arr : [undefined];

  myArray.flatMap(({ name, versions, targets }) => notEmpty(versions).flatMap(version => notEmpty(targets).map(target => ({ name, version, target }))));

Or with more dimensions, generators get very useful:

  function* cartesian(obj, key, ...keys) {
     if(!key) {
         yield obj;
         return;
     }

    const { [key + "s"]: entries, ...rest } = obj;
    for(const entry of (entries.length ? entries : [undefined])) {
        yield* cartesian({ [key]: entry, ...rest }, ...keys);
     }
 }

 myArray.flatMap(it => cartesian(it, "version", "target"))

You can use reduce method:

const result = myArray.reduce((a, {name, versions, targets}) => {
  versions.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });
  targets.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });  
  return a;    
}, []);

An example:

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]


const result = myArray.reduce((a, {name, versions, targets}) => {
  versions.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });
  targets.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
 });  
  return a;
}, []);

console.log(result);

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2'] },
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3'] },
  { 'name': 'c', versions: [1], targets: [] }
]

const reducer = (acc, current) => {
  const { name, versions, targets } = current;
  for (let i = 0; i < versions.length; i++) {
    acc.push({ name, version: versions[i], target: targets[i] })
  }

  for (let i = 0; i < targets.length; i++) {
    acc.push({ name, version: versions[i], target: targets[i] })
  }

  return acc;
}

const ungroup = array => array.reduce(reducer, [])

console.log(ungroup(myArray))

We can Un group the objects in the following way

const rows = [
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1579",
"clientName": "Apple",
"Id": 110117,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea53",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea54",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 2,
"bulkUploadErrorMessage": ""
  },
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1589",
"clientName": "Mango",
"Id": 110118,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea55",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea56",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 2,
"bulkUploadErrorMessage": ""
  },
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1599",
"clientName": "Orange",
"Id": 110119,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea57",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea58",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea59",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 3,
"bulkUploadErrorMessage": ""
  }
]

const mergeMF = input => {
const initObj = []
input.forEach(rootItem => {
    const { Id, clientName, manageFunds } = rootItem
    const groupId = rootItem.groupId
    manageFunds.forEach(subItem => {
        const newSubItem = {
            ...subItem,
            accountId: subItem.accountId,
            Id: Id,
            clientName: clientName,
            groupId: groupId,
        }
        initObj.push({
            checked: false,
            data: newSubItem,
            isCollapsed: false,
            validationErrors: subItem.errorMessages
        })
    })
})
return initObj
}

console.log(mergeMF(rows))

Think of an object array, each of them having certain array properties like versions, targets. I want to ungroup objects for each version and target. 

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]

Desired output for myArray above would be:

[
  { 'name': 'a', version: 1,         target: 'server1'},
  { 'name': 'a', version: 1,         target: 'server2'},
  { 'name': 'a', version: 2,         target: 'server1'},
  { 'name': 'a', version: 2,         target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server1'},
  { 'name': 'b', version: undefined, target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server3'},
  { 'name': 'c', version: 1,         target: undefined},
]

I pondered using nested for/forEach loops, but am almost pretty sure there must be a more precise and reasonable way of achieving it built-in es6 functions or so. And that's what I'm asking for.

Think of an object array, each of them having certain array properties like versions, targets. I want to ungroup objects for each version and target. 

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]

Desired output for myArray above would be:

[
  { 'name': 'a', version: 1,         target: 'server1'},
  { 'name': 'a', version: 1,         target: 'server2'},
  { 'name': 'a', version: 2,         target: 'server1'},
  { 'name': 'a', version: 2,         target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server1'},
  { 'name': 'b', version: undefined, target: 'server2'},
  { 'name': 'b', version: undefined, target: 'server3'},
  { 'name': 'c', version: 1,         target: undefined},
]

I pondered using nested for/forEach loops, but am almost pretty sure there must be a more precise and reasonable way of achieving it built-in es6 functions or so. And that's what I'm asking for.

  • javascript
  • arrays
  • ecmascript-6
Share Improve this question asked Dec 18, 2019 at 7:36 vahdetvahdet 6,75910 gold badges62 silver badges116 bronze badges 1
  • 1 There isn't a native method that I know of off-the-bat: I guess that's because what you're seeing essentially is creating all possible binations of versions + targets. That would call for a basic for loop, and it will grow in plexity the more dimensions you have, since the more nested the loops will have to be. – Terry Commented Dec 18, 2019 at 7:39
Add a ment  | 

4 Answers 4

Reset to default 6

You could use .flatMap:

  const notEmpty = arr => arr.length ? arr : [undefined];

  myArray.flatMap(({ name, versions, targets }) => notEmpty(versions).flatMap(version => notEmpty(targets).map(target => ({ name, version, target }))));

Or with more dimensions, generators get very useful:

  function* cartesian(obj, key, ...keys) {
     if(!key) {
         yield obj;
         return;
     }

    const { [key + "s"]: entries, ...rest } = obj;
    for(const entry of (entries.length ? entries : [undefined])) {
        yield* cartesian({ [key]: entry, ...rest }, ...keys);
     }
 }

 myArray.flatMap(it => cartesian(it, "version", "target"))

You can use reduce method:

const result = myArray.reduce((a, {name, versions, targets}) => {
  versions.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });
  targets.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });  
  return a;    
}, []);

An example:

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2']},
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3']},
  { 'name': 'c', versions: [1], targets: []}
]


const result = myArray.reduce((a, {name, versions, targets}) => {
  versions.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
  });
  targets.forEach((el, ind) => {
      a.push({name, version: versions[ind], target: targets[ind]})
 });  
  return a;
}, []);

console.log(result);

const myArray = [
  { 'name': 'a', versions: [1, 2], targets: ['server1', 'server2'] },
  { 'name': 'b', versions: [], targets: ['server1', 'server2', 'server3'] },
  { 'name': 'c', versions: [1], targets: [] }
]

const reducer = (acc, current) => {
  const { name, versions, targets } = current;
  for (let i = 0; i < versions.length; i++) {
    acc.push({ name, version: versions[i], target: targets[i] })
  }

  for (let i = 0; i < targets.length; i++) {
    acc.push({ name, version: versions[i], target: targets[i] })
  }

  return acc;
}

const ungroup = array => array.reduce(reducer, [])

console.log(ungroup(myArray))

We can Un group the objects in the following way

const rows = [
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1579",
"clientName": "Apple",
"Id": 110117,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea53",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea54",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 2,
"bulkUploadErrorMessage": ""
  },
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1589",
"clientName": "Mango",
"Id": 110118,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea55",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea56",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 2,
"bulkUploadErrorMessage": ""
  },
  {
"groupId": "ff686b1c-0d83-4e9e-ac0e-edd4ed7a1599",
"clientName": "Orange",
"Id": 110119,
"manageFunds": [
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea57",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea58",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  },
  {
    "accountId": "eb9e38a8-2e0e-46c2-b50a-fa5c7c18ea59",
    "address": {
      "address1": "",
      "city": "",
      "state": "",
      "zipcode": "",
      "country": ""
    }
  }
],
"size": 3,
"bulkUploadErrorMessage": ""
  }
]

const mergeMF = input => {
const initObj = []
input.forEach(rootItem => {
    const { Id, clientName, manageFunds } = rootItem
    const groupId = rootItem.groupId
    manageFunds.forEach(subItem => {
        const newSubItem = {
            ...subItem,
            accountId: subItem.accountId,
            Id: Id,
            clientName: clientName,
            groupId: groupId,
        }
        initObj.push({
            checked: false,
            data: newSubItem,
            isCollapsed: false,
            validationErrors: subItem.errorMessages
        })
    })
})
return initObj
}

console.log(mergeMF(rows))

本文标签： How to ungroup an object array based on multiple array properties in JavascriptStack Overflow

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