Pass PHP value to javascript using Ajax - Stack Overflow

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I have a php code that provides the database values. I need those values in the javascript variable.

Javascript Code

<script src=".8.0.js"></script>
<script type="text/javascript">
    function text() {
        var textVal=$("#busqueda_de_producto").val();
        $.ajax(
        {
            type:"POST",
            url:"index.php",  //here goes your php script file where you want to pass value
            data: textVal,
            success:function(response)
            {
               // JAVSCRIPT VARIABLE = varable from PHP file.
            }
        });

        return false;
    }
</script>

PHP FILE CODE:

<?php
    $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
    $res11 = mysql_query($q11);
    $row11 = mysql_fetch_array($res11);
?>

I have a php code that provides the database values. I need those values in the javascript variable.

Javascript Code

<script src="http://code.jquery./jquery-1.8.0.js"></script>
<script type="text/javascript">
    function text() {
        var textVal=$("#busqueda_de_producto").val();
        $.ajax(
        {
            type:"POST",
            url:"index.php",  //here goes your php script file where you want to pass value
            data: textVal,
            success:function(response)
            {
               // JAVSCRIPT VARIABLE = varable from PHP file.
            }
        });

        return false;
    }
</script>

PHP FILE CODE:

<?php
    $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
    $res11 = mysql_query($q11);
    $row11 = mysql_fetch_array($res11);
?>

• php
• javascript
• ajax-request

Share Improve this question Follow edited Sep 1, 2012 at 17:03 mtk 13.8k1616 gold badges7575 silver badges116116 bronze badges asked Aug 30, 2012 at 9:49 Harsimran SinghHarsimran Singh 74844 gold badges1313 silver badges2929 bronze badges 2

• 1 In your PHP code, just do echo json_encode($row11); – Ja͢ck Commented Aug 30, 2012 at 9:56
• if you just want to pass variables from one php page to another just use SESSION. you are just getting variable from a script and passing back to index.php what is the use of them in you html/javascript page ? – GajendraSinghParihar Commented Aug 30, 2012 at 9:56

Add a ment  | 

6 Answers 6

Sorted by: Reset to default 2

Your returning data is in the response parameter. You have to echo your data in PHP to get the results

Using JSON format is convenient

because of its key-value nature.

Use json_encode to convert PHP array to JSON.

echo the json_encoded variable

you will be able to receive that JSON response data through $.ajax

JavaScipt/HTML:

<script src="http://code.jquery./jquery-1.8.0.js"></script>
<script type="text/javascript">
    function text()
    {
        var textVal=$("#busqueda_de_producto").val();
        $.post('index.php', { codigo:textVal }, function(response) {
            $('#output').html(response.FIELDNAME);
        }, 'json');

        return false;
    }
</script>
<span id="output"></span>

PHP:

$q11 = "select * from sp_documentopra_detalle where dcd_codigo='".mysql_escape_string($_POST['codigo'])."'";
$res11 = mysql_query($q11);
$row11 = mysql_fetch_array($res11);

echo json_encode($row11);

You aren't echoing anything in your PHP script.

Try altering your PHP to this:

<?php
        $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
        $res11 = mysql_query($q11);
        $row11 = mysql_fetch_array($res11);

        echo $row11; //This sends the array to the Ajax call. Make sure to only send what you want.
?>

Then in your Ajax call you can alert this by writing alert(response) in your success handler.

Tips

Send your data to the server as a URL serialised string : request=foo&bar=4. You can also try JSON if you fancy it.

Don't use mysql_* PHP functions as they are being deprecated. Try a search for PHP Data Objects (PDO).

i see lots of things that needs to be corrected

the data in your ajax do it this way data: {'codigo':textVal}, since you are using $_GET['codigo'], which leads to the second correction, you used type:"POST" so you must also access the $_POST variable and not the $_GET variable and lastly the target of your ajax does not display / return anything you either echo it or echo json_encode() it

The best solution is to use echo json_encode("YOUR ARRAY/VALUE TO BE USED");

and then parse JSON in the javascript code as obj = JSON.parse(response);

I have a php code that provides the database values. I need those values in the javascript variable.

Javascript Code

<script src=".8.0.js"></script>
<script type="text/javascript">
    function text() {
        var textVal=$("#busqueda_de_producto").val();
        $.ajax(
        {
            type:"POST",
            url:"index.php",  //here goes your php script file where you want to pass value
            data: textVal,
            success:function(response)
            {
               // JAVSCRIPT VARIABLE = varable from PHP file.
            }
        });

        return false;
    }
</script>

PHP FILE CODE:

<?php
    $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
    $res11 = mysql_query($q11);
    $row11 = mysql_fetch_array($res11);
?>

I have a php code that provides the database values. I need those values in the javascript variable.

Javascript Code

<script src="http://code.jquery./jquery-1.8.0.js"></script>
<script type="text/javascript">
    function text() {
        var textVal=$("#busqueda_de_producto").val();
        $.ajax(
        {
            type:"POST",
            url:"index.php",  //here goes your php script file where you want to pass value
            data: textVal,
            success:function(response)
            {
               // JAVSCRIPT VARIABLE = varable from PHP file.
            }
        });

        return false;
    }
</script>

PHP FILE CODE:

<?php
    $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
    $res11 = mysql_query($q11);
    $row11 = mysql_fetch_array($res11);
?>

• php
• javascript
• ajax-request

Share Improve this question Follow edited Sep 1, 2012 at 17:03 mtk 13.8k1616 gold badges7575 silver badges116116 bronze badges asked Aug 30, 2012 at 9:49 Harsimran SinghHarsimran Singh 74844 gold badges1313 silver badges2929 bronze badges 2

• 1 In your PHP code, just do echo json_encode($row11); – Ja͢ck Commented Aug 30, 2012 at 9:56
• if you just want to pass variables from one php page to another just use SESSION. you are just getting variable from a script and passing back to index.php what is the use of them in you html/javascript page ? – GajendraSinghParihar Commented Aug 30, 2012 at 9:56

Add a ment  | 

6 Answers 6

Sorted by: Reset to default 2

Your returning data is in the response parameter. You have to echo your data in PHP to get the results

Using JSON format is convenient

because of its key-value nature.

Use json_encode to convert PHP array to JSON.

echo the json_encoded variable

you will be able to receive that JSON response data through $.ajax

JavaScipt/HTML:

<script src="http://code.jquery./jquery-1.8.0.js"></script>
<script type="text/javascript">
    function text()
    {
        var textVal=$("#busqueda_de_producto").val();
        $.post('index.php', { codigo:textVal }, function(response) {
            $('#output').html(response.FIELDNAME);
        }, 'json');

        return false;
    }
</script>
<span id="output"></span>

PHP:

$q11 = "select * from sp_documentopra_detalle where dcd_codigo='".mysql_escape_string($_POST['codigo'])."'";
$res11 = mysql_query($q11);
$row11 = mysql_fetch_array($res11);

echo json_encode($row11);

You aren't echoing anything in your PHP script.

Try altering your PHP to this:

<?php
        $q11 = "select * from sp_documentopra_detalle where dcd_codigo".$_GET['codigo']; 
        $res11 = mysql_query($q11);
        $row11 = mysql_fetch_array($res11);

        echo $row11; //This sends the array to the Ajax call. Make sure to only send what you want.
?>

Then in your Ajax call you can alert this by writing alert(response) in your success handler.

Tips

Send your data to the server as a URL serialised string : request=foo&bar=4. You can also try JSON if you fancy it.

Don't use mysql_* PHP functions as they are being deprecated. Try a search for PHP Data Objects (PDO).

i see lots of things that needs to be corrected

the data in your ajax do it this way data: {'codigo':textVal}, since you are using $_GET['codigo'], which leads to the second correction, you used type:"POST" so you must also access the $_POST variable and not the $_GET variable and lastly the target of your ajax does not display / return anything you either echo it or echo json_encode() it

The best solution is to use echo json_encode("YOUR ARRAY/VALUE TO BE USED");

and then parse JSON in the javascript code as obj = JSON.parse(response);

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