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I've made a simple function that adds a value to the array in javascript and then returns them.

What I can't return is the added value. What am I doing wrong?

It returns "c" instead of 3.

Fiddle /

Code:

function test(a, b, c) {
  var array = [a, b];
  array.push('c');
  alert(array);
}
test(1, 2, 3);

I've made a simple function that adds a value to the array in javascript and then returns them.

What I can't return is the added value. What am I doing wrong?

It returns "c" instead of 3.

Fiddle http://jsfiddle/0rapj8y8/2/

Code:

function test(a, b, c) {
  var array = [a, b];
  array.push('c');
  alert(array);
}
test(1, 2, 3);

• javascript

Share Improve this question Follow asked Oct 1, 2015 at 8:02 Ionut NeculaIonut Necula 11.5k44 gold badges4949 silver badges7272 bronze badges 3

• 2 array.push(c); - no '' - when you enclose c in quotes in it is treated as the string literal c, since you want to push the value referred by the variable c don't enclose it – Arun P Johny Commented Oct 1, 2015 at 8:04
• Hmm..my mistake. Thanks. – Ionut Necula Commented Oct 1, 2015 at 8:05
• I've made it a string. Saw that now. Thank you. – Ionut Necula Commented Oct 1, 2015 at 8:06

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 4

Very basic language syntax issue. Why do you quote a variable name?

array.push('c');  

That is a character c, not your variable c

array.push(c);  // that is now your variable c

Fiddle

Remove the quotes

function test(a, b, c) {
  var array = [a, b];
  array.push(c);
  alert(array);
}
test(1, 2, 3);

Remove Quote in push fuction as follows

function test(a, b, c) {
  var array = [a, b];
  array.push(c);
  alert(array);
}
test(1, 2, 3);

I've made a simple function that adds a value to the array in javascript and then returns them.

What I can't return is the added value. What am I doing wrong?

It returns "c" instead of 3.

Fiddle /

Code:

function test(a, b, c) {
  var array = [a, b];
  array.push('c');
  alert(array);
}
test(1, 2, 3);

I've made a simple function that adds a value to the array in javascript and then returns them.

What I can't return is the added value. What am I doing wrong?

It returns "c" instead of 3.

Fiddle http://jsfiddle/0rapj8y8/2/

Code:

function test(a, b, c) {
  var array = [a, b];
  array.push('c');
  alert(array);
}
test(1, 2, 3);

• javascript

Share Improve this question Follow asked Oct 1, 2015 at 8:02 Ionut NeculaIonut Necula 11.5k44 gold badges4949 silver badges7272 bronze badges 3

• 2 array.push(c); - no '' - when you enclose c in quotes in it is treated as the string literal c, since you want to push the value referred by the variable c don't enclose it – Arun P Johny Commented Oct 1, 2015 at 8:04
• Hmm..my mistake. Thanks. – Ionut Necula Commented Oct 1, 2015 at 8:05
• I've made it a string. Saw that now. Thank you. – Ionut Necula Commented Oct 1, 2015 at 8:06

Add a ment  | 

3 Answers 3

Sorted by: Reset to default 4

Very basic language syntax issue. Why do you quote a variable name?

array.push('c');  

That is a character c, not your variable c

array.push(c);  // that is now your variable c

Fiddle

Remove the quotes

function test(a, b, c) {
  var array = [a, b];
  array.push(c);
  alert(array);
}
test(1, 2, 3);

Remove Quote in push fuction as follows

function test(a, b, c) {
  var array = [a, b];
  array.push(c);
  alert(array);
}
test(1, 2, 3);

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