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I would like to simulate the C# Any() method, which can be used to determine whether if a collection has any matching objects based on a lambda expression.

I used jQuery's $.grep to make things easier:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, function (x, i) {
        return eval(expr);
    }).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any('x.a === 1')); //true
console.log(foo.any('x.a === 2')); //false

I know that eval() is bad practice for obvious reasons. But is it ok in this case, since I won't use this with anything related to some user inputs?

Can this be done without eval()? I can't figure out a way to pass an expression to the function without evaluating it.

/

I would like to simulate the C# Any() method, which can be used to determine whether if a collection has any matching objects based on a lambda expression.

I used jQuery's $.grep to make things easier:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, function (x, i) {
        return eval(expr);
    }).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any('x.a === 1')); //true
console.log(foo.any('x.a === 2')); //false

I know that eval() is bad practice for obvious reasons. But is it ok in this case, since I won't use this with anything related to some user inputs?

Can this be done without eval()? I can't figure out a way to pass an expression to the function without evaluating it.

http://jsfiddle/dgGvN/

Share Improve this question asked May 14, 2013 at 13:53 JohanJohan 35.3k62 gold badges189 silver badges306 bronze badges 3
  • 7 Can't you pass a function instead of an expression string? That would be more js-friendly. – bfavaretto Commented May 14, 2013 at 13:55
  • @bfavaretto: I think your ment makes a good answer. – nhahtdh Commented May 14, 2013 at 13:57
  • @nhahtdh I was too slow, now it would be pointless given the current answers. – bfavaretto Commented May 14, 2013 at 14:04
Add a ment  | 

2 Answers 2

Reset to default 9

I suggest you take a good look at JS closures. In particular, what you did there can be done natively in JS by using the Array.some method:

[{ a: 1, b: 2 }, { a:1, b: 3 }].some(function(x) { return x.a === 1; }); // true
[{ a: 1, b: 2 }, { a:1, b: 3 }].some(function(x) { return x.a === 2; }); // false

edit: in this case we're not really using closures but rather plain simple anonymous functions...

Pass in a function:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, expr).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any(function(x, i){return x.a === 1})); //true
console.log(foo.any(function(x, i){return x.a === 2})); //false

I would like to simulate the C# Any() method, which can be used to determine whether if a collection has any matching objects based on a lambda expression.

I used jQuery's $.grep to make things easier:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, function (x, i) {
        return eval(expr);
    }).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any('x.a === 1')); //true
console.log(foo.any('x.a === 2')); //false

I know that eval() is bad practice for obvious reasons. But is it ok in this case, since I won't use this with anything related to some user inputs?

Can this be done without eval()? I can't figure out a way to pass an expression to the function without evaluating it.

/

I would like to simulate the C# Any() method, which can be used to determine whether if a collection has any matching objects based on a lambda expression.

I used jQuery's $.grep to make things easier:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, function (x, i) {
        return eval(expr);
    }).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any('x.a === 1')); //true
console.log(foo.any('x.a === 2')); //false

I know that eval() is bad practice for obvious reasons. But is it ok in this case, since I won't use this with anything related to some user inputs?

Can this be done without eval()? I can't figure out a way to pass an expression to the function without evaluating it.

http://jsfiddle/dgGvN/

Share Improve this question asked May 14, 2013 at 13:53 JohanJohan 35.3k62 gold badges189 silver badges306 bronze badges 3
  • 7 Can't you pass a function instead of an expression string? That would be more js-friendly. – bfavaretto Commented May 14, 2013 at 13:55
  • @bfavaretto: I think your ment makes a good answer. – nhahtdh Commented May 14, 2013 at 13:57
  • @nhahtdh I was too slow, now it would be pointless given the current answers. – bfavaretto Commented May 14, 2013 at 14:04
Add a ment  | 

2 Answers 2

Reset to default 9

I suggest you take a good look at JS closures. In particular, what you did there can be done natively in JS by using the Array.some method:

[{ a: 1, b: 2 }, { a:1, b: 3 }].some(function(x) { return x.a === 1; }); // true
[{ a: 1, b: 2 }, { a:1, b: 3 }].some(function(x) { return x.a === 2; }); // false

edit: in this case we're not really using closures but rather plain simple anonymous functions...

Pass in a function:

Array.prototype.any = function (expr) {

    if (typeof jQuery === 'undefined')
        throw new ReferenceError('jQuery not loaded');

    return $.grep(this, expr).length > 0;

};

var foo = [{ a: 1, b: 2 }, { a:1, b: 3 }];

console.log(foo.any(function(x, i){return x.a === 1})); //true
console.log(foo.any(function(x, i){return x.a === 2})); //false

本文标签: jquerySimulate C Lambda methods in JavascriptStack Overflow