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I have written jquery for allowing numbers and dash - from being entered
$('.no-special-characters').keydown(function(e){
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 45) {
return true;
} else {
return false;
}
});
It does not work accordingly. It allows only numbers to be accepted.
I have written jquery for allowing numbers and dash - from being entered
$('.no-special-characters').keydown(function(e){
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 45) {
return true;
} else {
return false;
}
});
It does not work accordingly. It allows only numbers to be accepted.
Share Improve this question edited Sep 20, 2017 at 11:03 Rory McCrossan 338k41 gold badges320 silver badges351 bronze badges asked Sep 20, 2017 at 10:57 NidaNida 1,7023 gold badges36 silver badges75 bronze badges 1- Just as a side note, if you want to control what's in an input, you should check characters instead of the keyboard event. Because there are ways to enter characters in an input without explicitly typing it, for example pasting in the input. – Kewin Dousse Commented Sep 20, 2017 at 11:00
4 Answers
Reset to default 2try this code
$('.no-special-characters').keydown(function(e) {
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 189) {
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters">
Try this
Updated with backspace support
Allow the keycode of 189
$('.no-special-characters').keydown(function(e) {
var key = e.keyCode|e.which;
console.log(key) //check the key value in your console.log
if (key >= 48 && key <= 57 || key == 45 || key == 189 ||key == 8){
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters">
Here you go with one more solution
$('.no-special-characters').keydown(function(e){
if ((e.keyCode >= 48 && e.keyCode <= 57) || e.keyCode == 189) {
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters" type="text" />
Usually bine the keyCode
from 48 to 57
& then the next keyCode condition.
Hope this will help you.
e.keyCode = 109 is '-' on numpad
e.keyCode = 189 is '-' in alphabate keybord key on chrome
e.keyCode = 173 is '-' in alphabate keyboard key on firefox & on chrome 173 keycord is Mute On|Off
Source
Maybe this helps you, because using only e.keyCode == 189
(as some answers say) wont work in Firefox.
You can see, what keyCode
your key presses return here: Link
Edit: You can also use regular expressions. Then there is no need to add keyCodes for different browsers:
$('.no-special-characters').keypress(function(e){
var txt = String.fromCharCode(e.which)
var pattern = /^[0-9\-]+$/;
if (!(pattern.test(txt) || e.keyCode == 8)){
return false;
}
})
JSFiddle
I have written jquery for allowing numbers and dash - from being entered
$('.no-special-characters').keydown(function(e){
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 45) {
return true;
} else {
return false;
}
});
It does not work accordingly. It allows only numbers to be accepted.
I have written jquery for allowing numbers and dash - from being entered
$('.no-special-characters').keydown(function(e){
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 45) {
return true;
} else {
return false;
}
});
It does not work accordingly. It allows only numbers to be accepted.
Share Improve this question edited Sep 20, 2017 at 11:03 Rory McCrossan 338k41 gold badges320 silver badges351 bronze badges asked Sep 20, 2017 at 10:57 NidaNida 1,7023 gold badges36 silver badges75 bronze badges 1- Just as a side note, if you want to control what's in an input, you should check characters instead of the keyboard event. Because there are ways to enter characters in an input without explicitly typing it, for example pasting in the input. – Kewin Dousse Commented Sep 20, 2017 at 11:00
4 Answers
Reset to default 2try this code
$('.no-special-characters').keydown(function(e) {
if (e.keyCode >= 48 && e.keyCode <= 57 || e.keyCode == 189) {
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters">
Try this
Updated with backspace support
Allow the keycode of 189
$('.no-special-characters').keydown(function(e) {
var key = e.keyCode|e.which;
console.log(key) //check the key value in your console.log
if (key >= 48 && key <= 57 || key == 45 || key == 189 ||key == 8){
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters">
Here you go with one more solution
$('.no-special-characters').keydown(function(e){
if ((e.keyCode >= 48 && e.keyCode <= 57) || e.keyCode == 189) {
return true;
} else {
return false;
}
});
<script src="https://ajax.googleapis./ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input class="no-special-characters" type="text" />
Usually bine the keyCode
from 48 to 57
& then the next keyCode condition.
Hope this will help you.
e.keyCode = 109 is '-' on numpad
e.keyCode = 189 is '-' in alphabate keybord key on chrome
e.keyCode = 173 is '-' in alphabate keyboard key on firefox & on chrome 173 keycord is Mute On|Off
Source
Maybe this helps you, because using only e.keyCode == 189
(as some answers say) wont work in Firefox.
You can see, what keyCode
your key presses return here: Link
Edit: You can also use regular expressions. Then there is no need to add keyCodes for different browsers:
$('.no-special-characters').keypress(function(e){
var txt = String.fromCharCode(e.which)
var pattern = /^[0-9\-]+$/;
if (!(pattern.test(txt) || e.keyCode == 8)){
return false;
}
})
JSFiddle
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