admin管理员组文章数量:1026989
I would like to collect all info which can be fetched from user without ask any permissions. I don't want to use any of non-free ip info services and Geolocation
What I have now:
timeZoneOffset = new Date().getTimezoneOffset();
userLang = navigator.language || navigator.userLanguage;
But I want more info about users location.
I would like to collect all info which can be fetched from user without ask any permissions. I don't want to use any of non-free ip info services and Geolocation
What I have now:
timeZoneOffset = new Date().getTimezoneOffset();
userLang = navigator.language || navigator.userLanguage;
But I want more info about users location.
Share Improve this question asked Sep 17, 2020 at 13:58 Aleksandr_AAleksandr_A 3506 silver badges14 bronze badges 1- 1 That is not possible You can try this one for more accurate timezone for free stackoverflow./a/63915192/295783 – mplungjan Commented Sep 17, 2020 at 14:02
3 Answers
Reset to default 3Solution 1: The HTML Geolocation API is used to get the geographical position of a user.
- But it asked user for permission.
Solution 2: Free IP Location API
Check this: https://ipdata.co/
$.getJSON('https://geolocation-db./json/')
.done (function(location) {
$('#country').html(location.country_name);
$('#state').html(location.state);
$('#city').html(location.city);
$('#latitude').html(location.latitude);
$('#longitude').html(location.longitude);
$('#ip').html(location.IPv4);
});
Solution 3: PAID IP based API
There is no other solution for this.
The other answers mention paid services (ipdata) or free services without the data you need - timezone, etc - (geolocation-db.)
I believe Abstract has a free plan for their IP geolocation API that includes timezone data among others: https://www.abstractapi./ip-geolocation-api
$.getJSON("https://ipgeolocation.abstractapi./v1/?api_key=****************", function(data) {
console.log(data.ip_address);
console.log(data.country);
console.log(data.timezone);
})
You can use BigDataCloud's IP Geolocation API to get maximum data from the IP address of your website visitor.
It provides 10K queries per month for free.
https://www.bigdatacloud./ip-geolocation-apis/ip-address-geolocation-api
Output data:
{
"ip": "73.231.131.73",
"localityLanguageRequested": "en",
"isReachableGlobally": true,
"country": {
"isoAlpha2": "US",
"isoAlpha3": "USA",
"m49Code": 840,
"name": "United States of America",
"isoName": "United States of America (the)",
"isoNameFull": "the United States of America",
"isoAdminLanguages": [
{
"isoAlpha3": "eng",
"isoAlpha2": "en",
"isoName": "English",
"nativeName": "English"
}
],
"unRegion": "Americas/Northern America",
"currency": {
"numericCode": 840,
"code": "USD",
"name": "US Dollar",
"minorUnits": 2
},
"wbRegion": {
"id": "NAC",
"iso2Code": "XU",
"value": "North America"
},
"wbIneLevel": {
"id": "HIC",
"iso2Code": "XD",
"value": "High ine"
},
"callingCode": "1",
"countryFlagEmoji": "I would like to collect all info which can be fetched from user without ask any permissions.
I don't want to use any of non-free ip info services and Geolocation
What I have now:
timeZoneOffset = new Date().getTimezoneOffset();
userLang = navigator.language || navigator.userLanguage;
But I want more info about users location.
I would like to collect all info which can be fetched from user without ask any permissions.
I don't want to use any of non-free ip info services and Geolocation
What I have now:
timeZoneOffset = new Date().getTimezoneOffset();
userLang = navigator.language || navigator.userLanguage;
But I want more info about users location.
Share
Improve this question
asked Sep 17, 2020 at 13:58
Aleksandr_AAleksandr_A
3506 silver badges14 bronze badges
1
-
1
That is not possible You can try this one for more accurate timezone for free stackoverflow./a/63915192/295783
– mplungjan
Commented
Sep 17, 2020 at 14:02
Add a ment
|
3 Answers
Reset to default
3
Solution 1: The HTML Geolocation API is used to get the geographical position of a user.
- But it asked user for permission.
Solution 2: Free IP Location API
Check this: https://ipdata.co/
$.getJSON('https://geolocation-db./json/')
.done (function(location) {
$('#country').html(location.country_name);
$('#state').html(location.state);
$('#city').html(location.city);
$('#latitude').html(location.latitude);
$('#longitude').html(location.longitude);
$('#ip').html(location.IPv4);
});
Solution 3: PAID IP based API
There is no other solution for this.
The other answers mention paid services (ipdata) or free services without the data you need - timezone, etc - (geolocation-db.)
I believe Abstract has a free plan for their IP geolocation API that includes timezone data among others: https://www.abstractapi./ip-geolocation-api
$.getJSON("https://ipgeolocation.abstractapi./v1/?api_key=****************", function(data) {
console.log(data.ip_address);
console.log(data.country);
console.log(data.timezone);
})
You can use BigDataCloud's IP Geolocation API to get maximum data from the IP address of your website visitor.
It provides 10K queries per month for free.
https://www.bigdatacloud./ip-geolocation-apis/ip-address-geolocation-api
Output data:
{
"ip": "73.231.131.73",
"localityLanguageRequested": "en",
"isReachableGlobally": true,
"country": {
"isoAlpha2": "US",
"isoAlpha3": "USA",
"m49Code": 840,
"name": "United States of America",
"isoName": "United States of America (the)",
"isoNameFull": "the United States of America",
"isoAdminLanguages": [
{
"isoAlpha3": "eng",
"isoAlpha2": "en",
"isoName": "English",
"nativeName": "English"
}
],
"unRegion": "Americas/Northern America",
"currency": {
"numericCode": 840,
"code": "USD",
"name": "US Dollar",
"minorUnits": 2
},
"wbRegion": {
"id": "NAC",
"iso2Code": "XU",
"value": "North America"
},
"wbIneLevel": {
"id": "HIC",
"iso2Code": "XD",
"value": "High ine"
},
"callingCode": "1",
"countryFlagEmoji": "
本文标签：
Javascript get users location(countrylangtimezone)Stack Overflow
版权声明：本文标题：Javascript get users location(country, lang, timezone) - Stack Overflow 内容由热心网友自发贡献，该文观点仅代表作者本人，
转载请联系作者并注明出处：http://it.en369.cn/questions/1745218970a2140326.html，
本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容，一经查实，本站将立刻删除。
发表评论