javascript - regex that replace any chars (except number, .) - Stack Overflow

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I have a string. I need to parse it, replacing any chars (except numbers (0 to 9),, and ..

How can I do it with javascript?

Tried with :

string.replace(/[a-zA-Z]*/, "");

but seems it doesnt works. Also, I need ANY chars, not only a-Z (also ?, /, white space, and so on, expect, as said, , and .

I have a string. I need to parse it, replacing any chars (except numbers (0 to 9),, and ..

How can I do it with javascript?

Tried with :

string.replace(/[a-zA-Z]*/, "");

but seems it doesnt works. Also, I need ANY chars, not only a-Z (also ?, /, white space, and so on, expect, as said, , and .

• javascript
• regex

Share Improve this question Follow edited Oct 17, 2017 at 22:31 Felix Kling 816k180180 gold badges1.1k1.1k silver badges1.2k1.2k bronze badges asked Feb 13, 2012 at 14:02 markzzzmarkzzz 47.9k126126 gold badges316316 silver badges534534 bronze badges 1

• Create a negated character class: regular-expressions.info/charclass.html. Don't forget the global modifier. – Felix Kling Commented Feb 13, 2012 at 14:04

Add a comment  | 

4 Answers 4

Sorted by: Reset to default 13

Use a negated character class

[^0-9,.]

and put in any character you don't want to be replaced, it will match all the others.

See it here on Regexr

You can optimize it by adding a quantifier +, so that it replaces a sequence of those characters at once and not each by each.

string.replace(/[^0-9,.]+/g, "");

As Felix Kling pointed out, its important to use the global option g to match on all occurrences of the pattern.

See it here on Regexr

string.replace(/[^\d,.]+/g, "");

should do.

1. [^\d.,] means "any character except digit, comma or period", a negated character class.
2. Use + instead of * or you'll have lots of empty matches replaced with empty strings.
3. Use /g so all instances are replaced.

Try to replace all chars except digits and . , and do the replace globally:

string.replace(/[^0-9\,\.]+/g, "");

Try This Below code is prevent alpha key

onKeypress="return Custom(event,'[0-9]');"

function Custom(e, cPattern) {
    var key = [e.keyCode || e.which];
    var pattern = new String(cPattern);
    var keychar = String.fromCharCode([e.keyCode || e.which]);
    var pattern1 = new RegExp(pattern);

    if ((key == null) || (key == 0) || (key == 8) ||
                        (key == 9) || (key == 13) || (key == 27)) {
        return true;
    }
    else if (pattern1.test(keychar)) {
        return true;
    }
    else {
        e.preventDefault ? e.preventDefault() : e.returnValue = false;
    }
}

I have a string. I need to parse it, replacing any chars (except numbers (0 to 9),, and ..

How can I do it with javascript?

Tried with :

string.replace(/[a-zA-Z]*/, "");

but seems it doesnt works. Also, I need ANY chars, not only a-Z (also ?, /, white space, and so on, expect, as said, , and .

I have a string. I need to parse it, replacing any chars (except numbers (0 to 9),, and ..

How can I do it with javascript?

Tried with :

string.replace(/[a-zA-Z]*/, "");

but seems it doesnt works. Also, I need ANY chars, not only a-Z (also ?, /, white space, and so on, expect, as said, , and .

• javascript
• regex

Share Improve this question Follow edited Oct 17, 2017 at 22:31 Felix Kling 816k180180 gold badges1.1k1.1k silver badges1.2k1.2k bronze badges asked Feb 13, 2012 at 14:02 markzzzmarkzzz 47.9k126126 gold badges316316 silver badges534534 bronze badges 1

• Create a negated character class: regular-expressions.info/charclass.html. Don't forget the global modifier. – Felix Kling Commented Feb 13, 2012 at 14:04

Add a comment  | 

4 Answers 4

Sorted by: Reset to default 13

Use a negated character class

[^0-9,.]

and put in any character you don't want to be replaced, it will match all the others.

See it here on Regexr

You can optimize it by adding a quantifier +, so that it replaces a sequence of those characters at once and not each by each.

string.replace(/[^0-9,.]+/g, "");

As Felix Kling pointed out, its important to use the global option g to match on all occurrences of the pattern.

See it here on Regexr

string.replace(/[^\d,.]+/g, "");

should do.

1. [^\d.,] means "any character except digit, comma or period", a negated character class.
2. Use + instead of * or you'll have lots of empty matches replaced with empty strings.
3. Use /g so all instances are replaced.

Try to replace all chars except digits and . , and do the replace globally:

string.replace(/[^0-9\,\.]+/g, "");

Try This Below code is prevent alpha key

onKeypress="return Custom(event,'[0-9]');"

function Custom(e, cPattern) {
    var key = [e.keyCode || e.which];
    var pattern = new String(cPattern);
    var keychar = String.fromCharCode([e.keyCode || e.which]);
    var pattern1 = new RegExp(pattern);

    if ((key == null) || (key == 0) || (key == 8) ||
                        (key == 9) || (key == 13) || (key == 27)) {
        return true;
    }
    else if (pattern1.test(keychar)) {
        return true;
    }
    else {
        e.preventDefault ? e.preventDefault() : e.returnValue = false;
    }
}

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