Item 20:Facilitate the return value optimization.(More Effective C++)

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The rules for C++ allow compilers to optimize temporary objects out of existence. As a result, if you call operator* in a context like this,

Rational a = 10; 

Rational b(1, 2); 

Rational c = a * b;                          // operator* is called here 

your compilers are allowed to eliminate both the temporary inside operator* and the temporary returned by operator*. They can construct the object defined by the return expression inside the memory allotted for the object c. If your compilers do this, the total cost of temporary objects as a result of your calling operator* is zero: no temporaries are created. Instead, you pay for only one constructor call — the one to create c. Furthermore, you can't do any better than this, because c is a named object, and named objects can't be eliminated

转载于:https://wwwblogs/zhtf2014/archive/2012/03/09/2387538.html

The rules for C++ allow compilers to optimize temporary objects out of existence. As a result, if you call operator* in a context like this,

Rational a = 10; 

Rational b(1, 2); 

Rational c = a * b;                          // operator* is called here 

your compilers are allowed to eliminate both the temporary inside operator* and the temporary returned by operator*. They can construct the object defined by the return expression inside the memory allotted for the object c. If your compilers do this, the total cost of temporary objects as a result of your calling operator* is zero: no temporaries are created. Instead, you pay for only one constructor call — the one to create c. Furthermore, you can't do any better than this, because c is a named object, and named objects can't be eliminated

转载于:https://wwwblogs/zhtf2014/archive/2012/03/09/2387538.html

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